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EML 5060Analysis in Mechanical Engineering Fall 1998
Test 1 Van Dommelen (dommelen@eng.famu.fsu.edu) Due 8/28/98

Hand in the solution to this test on 8/28 (5% of your final grade). If your performance is insufficient, you will need to hand in a corrected version; however, only your initial grade counts. Please note: This test must have been accepted before exam 1, on 9/16, or you also receive a 0 grade for exam 1. Read carefully. And look it up.


Neatly draw the graph of the following functions, showing the locations of 0 and $\pm 1$ on each axis. Also give the derivative. Indicate nonprincipal values as a broken line. Make sure that you draw enough of the curves to clearly demonstrate all features.

\begin{displaymath}
1-x \qquad \qquad \qquad \qquad
x^2 - 2 \qquad \qquad \qquad \qquad
x^3 - x\end{displaymath}

\begin{displaymath}
\sin(x)\qquad \qquad \qquad \qquad
\arcsin(x)\qquad \qquad \qquad \qquad
\sinh(x)\end{displaymath}

\begin{displaymath}
\cos(x)\qquad \qquad \qquad \qquad
\arccos(x)\qquad \qquad \qquad \qquad
\cosh(x)\end{displaymath}

\begin{displaymath}
\tan(x)\qquad \qquad \qquad \qquad
\arctan(x)\qquad \qquad \qquad \qquad
\tanh(x)\end{displaymath}

\begin{displaymath}
\ln(x)\qquad \qquad \qquad \qquad
e^x\qquad \qquad \qquad \qquad
\cos(x^2)\end{displaymath}

Find (include any integration constants and absolute signs):

\begin{displaymath}
\int x^4 {\rm d} x= \qquad \qquad \qquad
\int_0^1 x^4 {\rm d} x = \qquad \qquad \qquad
\int_0^x \xi^4 {\rm d} \xi =\end{displaymath}

\begin{displaymath}
\int {{\rm d} x \over x} = \qquad \qquad \qquad
\int {1\over...
 ...m d} x = \qquad \qquad \qquad
\int {1\over 1 + x^2} {\rm d} x =\end{displaymath}

\begin{displaymath}
\int \ln(x) {\rm d} x = \qquad \qquad \qquad
\int x \sin(x) {\rm d} x = \qquad \qquad \qquad
\int x \sin(x^2) {\rm d} x =\end{displaymath}

\begin{displaymath}
\left\vert \matrix{
1 & 2 & 3\cr
1 & 2 & 6\cr
1 & 4 & 6}
\ri...
 ...uad
{{\rm d} \over {\rm d} x} \int_a^x f(\xi) g(x) {\rm d}\xi =\end{displaymath}

\begin{displaymath}
2 + 4 + 6 + 8 + \ldots + 998 + 1000 = \qquad \qquad\qquad\qq...
 ...ver \sqrt2} + {1\over \sqrt2^2} + {1\over \sqrt2^3} + \ldots = \end{displaymath}

\begin{displaymath}
{\rm Solve: }\quad{{\rm d} y\over {\rm d} x} = -y \qquad y(1)=1\end{displaymath}



'Author: Leon van Dommelen'